June 2013 Chemistry Regents #70-73

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  Base your answers to questions 69 through 71  on the information below.

 

In a laboratory apparatus, a sample of lead(II) oxide reacts with hydrogen gas at high temperature. The products of this reaction are liquid lead and water vapor. As the reaction proceeds, water vapor and excess hydrogen gas leave the glass tube. The diagram and balanced equation below represent this reaction.

70 Determine the change in oxidation number for the hydrogen that reacts. [1]

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0 to +1

71 Write a balanced half-reaction equation for the reduction of the Pb2+ ions in this reaction. [1]

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Pb2+ + 2e- ==> Pb

72 Explain why the reaction that occurs in this glass tube can not reach equilibrium. [1]

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The glass tube is not a closed system.

Gases are entering and leaving the system.

The reaction is reversible under these conditions.

73 State one change in reaction conditions, other than adding a catalyst, that would cause the rate of this reaction to increase. [1]

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Increase the temperature.

Increase the concentration of the hydrogen gas in the tube.

Grind the metal oxide to increase its surface area.

on to Questions 74-77

 

 

 

Questions 1-10 Questions 11-20 Questions 21-30 Questions 31-40 Questions 41-50

Question 51-53 Questions 54-56 Questions 57-59 Questions 60-62 Questions 63-65 Questions 66-69 Questions 70-73 Questions 74-77  Questions 78-80  Questions 81-82  Questions 83-85

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