Back to Acid Base Links
Strong Bases- Strong bases are Group 1 or group 2 hydroxides. Strong bases is pretty much the same as strong acids EXCEPT you'll be calculating a pOH first, then going to the pH.
pH + pOH = 14
pH = 14- pOH
Calculate the pH of a 0.0010 M solution of NaOH.
NaOH==> Na+ + OH-
Therefore, the [OH-] equals 0.0010 M. So, to solve it, you write:
pOH = - log (0.0010) = 3.00
pH = 14.000 - 3.00 = 11.00
Calculate the pH of a 0.025 M solution of Ca(OH)2 .
Ca(OH)2 ==> Ca2+ + 2OH-
Therefore, the [OH-] equals 0.050 M. For every Ca(OH)2 you produce 2OH-.
pOH = - log (0.050) = 1.70
pH = 14.000 - 1.70 = 12.30