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Here are the equations you could use.

pH + pOH=14

pH =-log[H⁺]   [H⁺]=10^-pH

pOH=-log[OH^-]    [OH^-]=10^-pOH

^{Here is a table that needs to be complete.}

Example A

     If pH= 6.1 and pOH=14-pH          pOH=14-6.1=7.9

    [H⁺]=10^-pH   so  [H⁺]=10^-6.1              [H⁺]=7.9x10^-7M

    [OH^-]=10^-pOH so  [OH^-]=10^-7.9      [OH^-]=1.2x10^-8M

Example B

     If pOH= 3.7 and pH=14-pOH          pH=14-3.7=10.3

    [H⁺]=10^-pH   so  [H⁺]=10^-10.3              [H⁺]=5.0x10^-11M

    [OH^-]=10^-pOH so  [OH^-]=10^-3.7      [OH^-]=2.0x10^-4M

Example C

     If [H⁺]=1.5x10^-6M and pH =-log[H⁺] 

     pH =-log1.5x10^-6M                                 pH=5.82

    If pH= 5.82 and pOH=14-pH          pOH=14-5.82=8.18

    [OH^-]=10^-pOH so  [OH^-]=10^-8.18      [OH^-]=6.6x10^-9M

Example D

     If  [OH^-]=8.1x10^-4M and pOH =-log[OH^-]

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