Gay- Lussacs Law- This law describes the relationship between temperature and pressure changes with constant volume.
P= Pressure T=Temperature in Kelvin
Sample Problem #1-
Find the final pressure of gas at 150. K, if the pressure of gas is 210. kPa at 120. K if the volume remains constant.
cross-multiply and get P2 by itself.
T1=(210.kPa)(150.K)/120.kPa = 263 kPa
Sample Problem #2
A cylinder contain a gas which has a pressure of 125kPa at a temperature of 200. K. Find the temperature of the gas which has a pressure of 100. kPa if the volume remains constant.
Answer-->How nice the temperature is already in Kelvin (a gift).
cross-multiply and get T2 by itself.
T2=(100.kPa)(200.k)/125kPa = 160.K