Gay Lussac's Law

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Gay Lussac's Law

Gay- Lussacs Law- This law describes the relationship between temperature and pressure changes with constant volume.

P1	=	P2
T1	=	T2

P= Pressure T=Temperature in Kelvin

Tires explode when a car or truck is on fire. Temperature increases and Pressure increases (volume remains the same)

Explosion at 25 seconds

Explosion at 2:40

Sample Problem #1-

Find the final pressure of gas at 150. K, if the pressure of gas is 210. kPa at 120. K if the volume remains constant.

P1	=	P2
T1	=	T2

so,

210.kPa	=	P2
120.K	=	150.K

cross-multiply and get P2 by itself.

T1=(210.kPa)(150.K)/120.kPa = 263 kPa

Sample Problem #2

A cylinder contain a gas which has a pressure of 125kPa at a temperature of 200. K. Find the temperature of the gas which has a pressure of 100. kPa if the volume remains constant.

Answer-->How nice the temperature is already in Kelvin (a gift).

P1	=	P2
T1	=	T2

so,

125kPa	=	100 kPa
200 K	=	T2

cross-multiply and get T₂by itself.

T₂=(100.kPa)(200.k)/125kPa = 160.K

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