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Gay- Lussacs Law- This law describes the relationship between temperature and pressure changes with constant volume.
P= Pressure T=Temperature in Kelvin
Sample Problem #1- Find the final pressure of gas at 150. K, if the pressure of gas is 210. kPa at 120. K if the volume remains constant.
so,
cross-multiply and get P2 by itself. T1=(210.kPa)(150.K)/120.kPa = 263 kPa Sample Problem #2 A cylinder contain a gas which has a pressure of 125kPa at a temperature of 200. K. Find the temperature of the gas which has a pressure of 100. kPa if the volume remains constant. Answer-->How nice the temperature is already in Kelvin (a gift).
so,
cross-multiply and get T T |